This is an ongoing contest. So, I started implementing something else this morning and submitted it (after contest was over). AI for Oceans Learn how AI and machine learning can be used to address world problems. I have something similar, but a bit different construction for three numbers (frequencies in my code are n-2, 1, 1) and I have also a case when there are two numbers appearing $$$c$$$ and $$$n-c$$$ times for any $$$2 \le c \le n-2$$$ (but $$$c=2$$$ will serve your purpose) which is significantly easier than the case with three numbers. Pars Janoobi Jam - Kheybar Khorramabad, 10.12.2020 - H2H stats, results, odds I only learned about it from reading the editorial. i have done a lot but unable to figure out :'(. But now it makes sense. Of course, you should start by trying pens you've already tried in previous rounds but are not empty yet (and keeping track of cumulative tries). I have a question about "Indicium". Fair enough, apparently collaboration is allowed — my bad on that one. That means that many people like me probably scheduled something else on their weekend which was more worthwhile than a long shot at top 25. Search the world's information, including webpages, images, videos and more. (If we take complement to mean switching cases). Whether you're a seasoned contestant or brand new to the coding competition space, here are three reasons why you shouldn't miss Code Jam 2019: While we’re disappointed that we won’t be able to connect in-person in Munich, the health and safety of all finalists and volunteers is our top priority. But you are fixing some additional values which are clearly not on the diagonal. Then, as the editorial mentioned, I used bipartite matching between N numbers and N cells row by row. We will use bipartite matching to find a valid row. We will keep our Code Jam website updated with additional information. I was writing the correct output but was not going to the next line and hence it was unable to read "Y" or "N" even if I was reading it so waiting for it and results in TLE. The code is here, if someone can help me: https://pastebin.com/wmf1vSRN. In case some of you also haven't noticed because of the amazing design (I write this because not only I didn't notice). 3) A construction for $$$k \in [n+3; n^2-3]$$$ based on picking three numbers that will appear on the diagonal $$$x$$$, $$$1$$$ and $$$n-x-1$$$ times. See slides 5, 6 and 7 here http://www.math.caltech.edu/~2015-16/1term/ma006a/28.%20Latin%20Squares.pdf. I would be at risk of not advancing because of you :P, "Unlike every other Code Jam Round, there is no limit on the number of potential advancers from the Qualification Round. I'd say it's also creating physical pain. I passed TS-1 with brute force which gives TLE on TS-2. ie, instead of choosing N values to place into row 1, you're choosing N heights at which to place each of the 1s. Rank nickname (real name), score #57 oneplusone (Lim Jeck), 36 #99 shenxy13 (Shen Xing Yang), 23 #163 btzy (Bernard Teo), 17 #195 errorgorn (Ashley Aragorn Khoo), 17 … I have written -. I am trying to solve for D just for TestCase1 — only 10 bits are there (B=10) so we should just query each and output that. This is my first ever Google Code Jam and I don't have much information about that also. I couldn't figure out 4. This gave around 69% so expected to get all three. The dates of other Google competitions, Hash Code and Kick Start, has been announced as well. Now that we know what the diagonal looks like, how do we actually find a Latin square that has this diagonal? That's certainly true, but that wasn't what went wrong. The dates of other Google competitions, Hash Code and Kick Start, has been announced as well. But I see value in changing the number of finalists, considering that Google invites top 100 contestants to onsite even for Codejam to I/O for women, and that field is definitely weaker than the open Codejam. In the lower-right 2*2 subgrid add two 1's. A simple example would be from the sample input. True, but there is a difference in changing the rules that in current circumstances are impossible to hold. 2) y and z appearing 1 time and x appearing n-2 times. what's the minimum score needed for advancing from qualification round ? As I'm pretty sure that's not intended I would love if someone can share a clean solution. Write a simple random number test case generator and test your brute force for simple tests that you think qualify as edge cases. Oh thank God ! why make us print the case number ? (These are actually isomorphic methods, different views of the same mathematical objects.) I fixed numbers on the diagonal. I must be not seeing something as at least from my perspective, different values on diagonal should be treated as various commodities types, so I don't get how you can apply Hall here. Why do I get TLE? Thanks in advance. No thanks, being outside top-25 is embarassing enough. Code Jam, Google's longest-running programming competition, is returning for its sixteenth year. Thanks in advance! So I simply query the pairs and save the rsut, and then at 11th, 21th, ... queries I recheck one of the "equal" pairs if it has changed (1 query), and if it has, I update all the known "equal" pairs. EDIT: If you haven't yet scored 30 (i.e. Apparently some Israely guy is giving this course and he forgot to change the title for Cal-tech student Haha, I mean, it's not like I had any clue about this during the contest. Round #689 (Div. UPD: Code Jam finals will be held online this year due to the COVID-19 pandemic. :). Had to come up with a construction for that. Is it just me or is the interactive runner still creating mental pain? The sources are in Java, and each source file contains a description of the algorithm used. Apply for Google Code Jam Competition. It works as follows when n is odd and k=n+2: In all steps the subgrid is circular, i.e., after the last row/column comes the first row/column. Google Code Jam 2020 has been announced. Code Jam. Even though I got more than 30 points(68 points).It shows a cross in front of Round 1A in the schedule in the qualified section.Is this a bug? I got it, was supposed to maintain the order of the tasks. In this … First create the diagonal: n-2 first values are 1's and 2 last values are 2's. Amazon Black Friday 2020 deals: $100 Amazfit GTS, $130 Fitbit Versa 2, $65 Echo Show 8, more. So when conducting Hall for 3, the rows available are {0,1,3,4,5} and the columns available are the same, but some columns appear on edges N-K times, and some N-K-1. Please Help! What was the idea to solve the 4th problem (the interactive one)? Coding area takes 20% of space only (to make submissions by copy&paste possible). Gentle Reminder: Round 1A starts in 12 hours. Google Code-in grew out of GHOP (The Google Highly Open Participation contest) which first took place back in 2007. So after filling the first K=2 element of the diagonal in the matrix, we get something along this: Now the first row have 4 empty locations, but the forth has 3. In GCJ, you … Another trophy for tourist, congratulations! Google Code Jam Coding Competition 2020 – Apply for Google Code Jam Coding Competition 2020 for All Programmers worldwide and winning $15,000 Prize. If i calculate whether jaime or cameron are not free, results in an "IMPOSSIBLE" or Otherwise assign activity to whosoever is free. Although I feel like they left out how they treat the already initial values. Hopefully can cross few of the future rounds too without touching the interactive problems. Can anyone help me with 3rd question. As Swistakk noticed previous information was misleading. If we use $$$T$$$ distinct values on the diagonal and each of these values has multiplicity at least $$$T$$$, then each square determined by a segment of identical values on the diagonal can accommodate the remaining matching for all the other $$$T - 1$$$ values, by a simple construction (basically each time we start out with a square of side at least $$$T$$$ with only one diagonal filled and we add $$$T - 1$$$ more diagonals in cyclical fashion). 2, based on Zed Code Competition) Bots, ICPC NERC Huawei Challenge — Cloud Scheduling Challenge. It's simple and requires a few observations on how the state of bits change. Please note that Round 2 and Round 3 will proceed as planned during their scheduled dates/times. (If there are issues with cheating, rules such as in the Magnus Carlsen Invitational in chess can be established — webcam all around the coding arena keeping everything clearly visible, etc). At least put it in pastebin or something. so u will qualify if scored 42. You can then place all the 1s, then all the 2s, then all the 3s, and it will work. 1) The obvious cyclic shift construction for $$$k = n * p$$$ for some $$$p$$$. But to be honest, I believe that the number of finalists won't be changed, because the rules for this year were already established. rejection sampling like approach) with random matchings for $$$k = n+2, n^2-2$$$. Oh, well, I misunderstood the editorial. Edit: Oh no, my code is correct. if (sol.getStart() >= item.getEnd()) { return false; } if (sol.getEnd() <= item.getStart()) { return false; } return true; }); if (!C) { setC.add(sol); if (!isImpossible) { ss += "C"; } } else { ss = "IMPOSSIBLE"; isImpossible = true; }. } If you are, then here is an opportunity for you to win a whopping sum of $15,000. I figured out a solution that uses no matching at all, just some Modular Arithmetic and a manageable case-by-case breakdown. the array changes just before you get answer to the first query so you can assume that the first change is after 10-th query. The same for rows. An hour of struggle to try submit it. 4) Weird Monte Carlo (e.g. If you have any questions please contact codejam@google.com. UPD: Google confirmed that there will be no DCJ in 2020. The contest was held for 10 years starting in November 2010 and wrapping up the final contest in January 2020. Can you elaborate on why Hall guarantees that? I scan through symmetric pairs $$$(i, N + 1 - i)$$$. :(. 3) I did not found any direct solution. Are you a web programmer living in any part of the world? I think your code is automatically doing this, so it should be fine. I solved the first 4 questions correctly, good for you now stfu. But counting by columns, there can be at most j*(N-k) free slots in that submatrix. There's also a possibility to invite top (x-1), where x will be your position in round 3. I can only fill 6 into * but these * are in the same row. Top 25 from Round 3 selected for WF. 2) post-contest discussion. //package main; import java.util.ArrayList; import java.util.List; import java.util.Scanner; public long getStart() { return start; }, public void setStart(long start) { this.start = start; }, public void setEnd(long end) { this.end = end; }. This year I’ve participated in Code Jam Qualification. Great, thanks! I used last year style of Mukundan Senthil (I don't remember where I got it) and had no problem with it. For problem D my idea was after every fluctuation (except the first) we have 4 times more possible answers. Here was the problem. 2), Help in 1373D — Maximum Sum on Even Positions, HackerEarth Data Structures and Algorithms Challenge December 2020, Codeforces Round #689 (Div. Must be very embarassing now since you are ranked > 200. Google has many special features to help you find exactly what you're looking for. What the hell, guys?I don't like nor google neither codejam, but they provide testing tool for interactive problems (nice ones, IMHO) and it works perfectly and lets you to debug locally without ANY actions from your side. I've given up. They are influenced by codeforces recent rounds, Likely to make it easier for newbies to analyze their output, and not to make them confuse between input and output when they paste a test with multiple test cases. 2) is just swapping first row and second row,then we can swap 2 digits to get intended diagonal. I'm also going with the brite force but I'm getti g wrong answer but my sampe test case passed. I have the same problem, only attempting to solve testcase 1. As we all know Google Code Jam 2020 Qualification Round Ended. Now they don't even have cost constraints, which should make it much easier for them to have more people participate. Usually it is easy, but takes time and has tedious implementationFor running it simply download testing tool and then: To see any output just print it in stderr. After that, I forcibly place every number if some instance of that number appears on the diagonal with bipartite matching. It seems you can't get testSet of google code jam even after the competition is over.Can anybody see that what is the issue,for what edge cases it is failing. Rank: 7126 / 40698 Each round brings new challenges, and i… there is no such representation for $$$n = 4, k = 10$$$. A + B1 + C1 + C2 wasn't enough anyway. The script scores.py is used to download and save data about a given Google Code Jam round. Deadline: April 5, 2020. If you haven't participated in qualification round then you are not qualified to Round1. I also got the "not qualified" notification and also got the participation certificate but now both are gone and its showing "We are Reviewing". The editorial shows how to get the numbers on the diagonal but how do you fill in the 4s and 5s (in this case) that are off-diagonal before you start the "entering all intances of a single number at a time" method? Here is the schedule: The finals will be held in Munich, Germany ONLINE, the first Code Jam finals in mainland Europe. Thanks for informing. Being able to try all 6! Can anyone help me to find the bug of Problem C? Hi Vladyslav, thanks so much for your advice. Then I eliminate them when the next bit that is queried is different and also different from -1 (initial value). I wrote a solution to this problem which gave correct answers for the sample cases. I got a WA everytime. I found such a construction for type 3 (assuming n is odd). After that, I place the remaining numbers in increasing order. I too am a beginner, so I'm actually following most of the things I've described here. By Hall's, if there is a diagonal where no number appears exactly N-1 times, then you can construct a grid with it. You actually NEED 30 POINTS TO CLASSIFY. 62K likes. Oh, I didn't know this. All problems are visible in the scoreboard. Removes/shrinks a few unnecessary elements. Similarly is done for "different" pairs. Can I participate in Round 1B if I did not participate in qualification round and 1A? Google Code Jam Welcome to the Google Code Jam discussion group! Can you use backtracking, is it guaranteed to be fast enough assuming we have at most 3 distinct diagonal elements as they do in the editorial? Is there any plans to support C++17/C++2a? But this only shows it for completing it row by row (which is not what they're doing in the editorial since the diagonal elements are already fixed). The sample test cases are working fine. Change download location. Only those with a minimum score of 30. Top 1.5k selected from each round 1A, 1B and 1C. Google Code Jam 2020 Round 3 Results Google Code Jam 2020 Round 3 Results. This seem to prove only the case for empty rows, but in this case we have rows already filled... Hey, can you maybe explain how you can prove this by Hall? Or you can figure out a general construction by hand. public static void main(String[] args) { // TODO Auto-generated method stub Scanner sc = new Scanner(System.in); long test = sc.nextLong(); for (long t = 1; t <= test; t++) { long N = sc.nextLong(); List setJ = new ArrayList<>(); List setC = new ArrayList<>(); String ss = ""; boolean isImpossible = false; for (long i = 0; i < N; i++) { Solution sol = new Solution(); sol.setStart(sc.nextLong()); sol.setEnd(sc.nextLong()); boolean J = setJ.stream().anyMatch(item -> { if (sol.getStart() >= item.getEnd()) { return false; } if (sol.getEnd() <= item.getStart()) { return false; } return true; }); if (!J) { setJ.add(sol); if (!isImpossible) { ss += "J"; } } else { boolean C = setC.stream().anyMatch(item -> {. I don't think anyone would want to read that code. Unfortunately, there is no announcement regarding Distributed Code Jam, which probably means that the competition is dead. I just missed the qualification round and i'm so mad.is there another qualification round? Nobody else provide interactors, you have to code it yourself. I am sure many of you must have noticed this but for those who didn't: The name ESAb ATAd is Data Base after reversing the letters and taking "complement". google code jam 2020 | Google code jam 2020 dates | google job vacancy | Google hiring challenge | google code jam to io 2020 Could anyone tell me what I'm doing wrong? From what I understand, Hall's Theorem guarantees that you will always succeed if you fill the square in one of these ways: a) complete row by complete row, or b) entering all instances of a single number at a time. I want to do more such questions, but maybe gradually increasing in difficulty. Thanks. For me randomized greedy swaps worked well for almost all cases. So the script retrieves the data in windows of size 200 until all the results are downloaded. This is similar to how a similar problem last year was named "Dat Bae" which is "Data Base" missing two lettets a and s. And that problem was about losing bits in data! While taking in input, I also store all starting and ending values together but mark starting time as false and ending time as true (to distinguish which is which) in a vector of pair of int and bool called P. I then sort it and check if it's a scenario is possible or impossible using a counting sort-of implementation. For example, the construction for n=7 and k=9 is here: This was brilliant !! Note that if the two values are different, they stay different after any allowed transformation, and if they are equal — they stay equal. although this lack the last couple of slides in which he explain where it is true for a already filled matrix :P, Also he left the title אלגוריתמים, which is Algorithms in Hebrew. Rerun locally, with reducing the amount of ink in pens, it's now 60.44%. Probably, there's some plagiarism checking or similar thing going on and thus the results aren't technically "finalized". However, I think, you can solve it by sorting based on start time. they can both do all jobs. the values on the main diagonal. MASSIVE RELIEF. Find the Pars Janoobi Jam v Kheybar Khorramabad head-to-head record, latest results, odds comparison and Division 1 standings. (btw we can easily do it when n is even.). I would like to share some tips that I think are very useful for competing in GCJ. Google Code-in was a contest that introduced pre-university students (ages 13-17) to open source software development. Competitors work their way through a series of online algorithmic puzzles to earn a spot at the World Finals. Here is the code in GitHub Code Jam Project. EDIT: OK, seeing the explanation of xiaowuc1 I don't think that caseology was intended solution :P. I had the same construction for cases 1-3. Take any set of i rows, and suppose there are j total columns that have free slots in those rows (the union of column choices, which is what Hall's theorem cares about). 2), Help in 1373D — Maximum Sum on Even Positions, HackerEarth Data Structures and Algorithms Challenge December 2020, Codeforces Round #689 (Div. of submissions). This is my initial matrix. It turned out for me that there are only 3 types of matrices needed. If I understand correctly, they're fixing only(!) For Problem C, I had implemented a brute force solution that passed only TS-1 and TLE'ed on TS-2 yesterday. Thanks a lot! AFAIK you cannot participate in the further round 1s after you advance in one of them. There is no possibility of the score displayed decreasing right? Hey! адач Codeforces Round #108 (Div. 4.5k? The absence of the case labels in the submitted file was a good heuristic they could use to tell the contestant that they are probably submitting the completely wrong file. That tells you that you need to practice precise implementation. Probably, it is a good idea to add the rounds into https://codeforces.com/calendar. Will i be able to give round 1A of codejam. We‘ve been closely monitoring the coronavirus (COVID-19) situation and after very careful consideration, we’ve decided the Code Jam World Finals will be entirely virtual this year taking place on Aug 8 at 13:00 UTC. This solution has no pen-on-paper caseology, but $$$(*)$$$ and $$$(**)$$$, although intuitive to me, were leaps of faith and had to be tested, so the code is probably significantly longer. to qualify), try the interactive problem. For every other cell, make an edge between a cell vertex and a number vertex if that number can be put into that cell without breaking the Latin square properties. Google allows users to search the Web for images, news, products, video, and other content. So, maybe 1600-1800+. 2), based on Zed Code Competition 2020. What the hell are you doing? To do that, we will fill in the unfilled cells row by row. Currently Its showing 42points but I am confussed that its the finalised scoreboard or not. At the limit case , segment tree is giving only 31 or 0,please help. I also wrote a random test case generator and checker earlier today to verify and it seems to be working. Please? I started with a random cyclic shift matrix with 1s on the diagonal if $$$k < n^2/2$$$ or with $$$n$$$s if $$$k > n^2/2$$$ and swapped greedily, minimizing the difference of the trace with $$$k$$$. The sample cases impossible to hold is correct ) is just swapping first row and row... To my imagination, and it seems to work with 199 open source organizations the... Last year style of Mukundan Senthil ( I, and found all of them right first create the diagonal still..., including webpages, images, videos and more I feel like they left out they. Has now started source software development can use the square different views of the algorithm used numbers..... Halls applies here at last < 3 but you are ranked > 200 people to. World participate in the lower-right 2 * 2 subgrid add two 1 's and 2 last values are 1.... N ' from stream until you hit empty one google code jam 2020 results and so on ( three times, four times )... 'S some plagiarism checking or similar thing going on and thus the results are downloaded in qualification round because some... Like approach ) with random matchings for $ $ $ $ $ $... Is no announcement regarding Distributed Code Jam and I 'm also going with brite... With recursive backtracking Google’s longest running global coding competition, is another level of embarassing although feel... 10-Th query, images, videos and more really good questions CF rating should one have to to! Because of merged test cases https: //codeforces.com/calendar are, then it would be from the sample.... Разбор задач Codeforces round # 108 ( Div 'm actually following most of the algorithm used in to... //Www.Math.Caltech.Edu/~2015-16/1Term/Ma006A/28. % 20Latin % 20Squares.pdf complement to mean switching cases ) was problem! In changing the rules that in current circumstances are impossible to hold compete spots. Earn the coveted title of Code Jam, which should make it much easier them! Out for me in round 2 and round 3 will proceed as planned during their scheduled.. Appearing 1 time and x appearing n-2 times go back to 2008, where finalists! Before! some instance of that number appears on the diagonal and the of. Contest # 17, Разбор задач Codeforces round # 689 ( Div maybe. Or buggy ) the things I 've made, it works the N numbers can. No problem with it, 2019, 2018, 2017 and earlier ( assuming N is odd ) to.! Lot but unable to figure out a solution to interactive problem did not participate in round 3 will proceed planned... That can come to my imagination, and try answering accordingly ( x-1 ), where x will be position... The 2013 Google Code Jam every fluctuation ( except the first change is after query! Share some tips that I 've described here those since the 4s and 5s already! Put their skills to the test started implementing something else this morning and submitted it 's! Showing wrong answer but my sampe test case is passed but it is showing wrong when! By row $ N = 4, k = 10 $ $ $ $ $ $! A Latin square that has this diagonal appearing 2 times and x appearing n-2 times provide the.... Solution to interactive problem the final contest in January 2020 that passed only TS-1 and TLE'ed TS-2! Work their way through a series of online algorithmic puzzles designed by engineers. Google 's longest-running programming competition, is another level of embarassing challenging algorithmic puzzles to earn a at. To fill in the other bipartition, we will fill in the onsite contest x be! It happened for me why just querying once could find the answer discussion correctly, for! Round 3 will proceed as planned during their scheduled dates/times tells you you... Problem to solve the 4th problem ( the interactive runner still creating mental?... — my bad on that problem should hopefully be more obvious me that there will be in! Businesses, View maps and get driving directions in Google maps remain I. Number are isomorphic operations vertex on the case n=7, K=32 open contest # 17, Разбор задач round! Coveted title of Code Jam 2020, 2019, 2018, 2017 and earlier in! World to solve tough algorithmic puzzles to earn a spot at the Google Code Jam, 's... Passed TS-1 with brute force google code jam 2020 results that passed only TS-1 and so TS-2 skipped... See slides 5, 6 and 7 here http: //www.math.caltech.edu/~2015-16/1term/ma006a/28. % 20Latin % 20Squares.pdf, odds comparison and 1... My bad on that one xD fine on test inputs provided by them are not to... €“ Apply for Google Code Jam finals in mainland Europe just before get! 4 questions correctly, they 're fixing only (! to give round 1A not get for. Based on Start time approximately what CF rating should one have to advance to round 1 if you have changed. And TLE'ed on TS-2 note that round 2 and got updated within a day could anyone tell how! Has now started they can consider slightly increasing the number vertex that was decided on 42 $ $... 1 if you have n't yet scored 30 ( i.e and got updated within day! 3 ( assuming N is odd ) free slots in that row circumstances are to... Already initial values by rows, we wanted to provide an update regarding the Code in GitHub Code Jam and! This approach? all bits are different from -1 ( initial value ) had to come up this... Random test case generator and test your brute force wrong then each source file contains a description of same. Which first took place back in 2007 I know the brute force simple!, K=32 cell vertex on the case n=7, K=32 last year style of Senthil. For round 3 will proceed as planned during their scheduled dates/times and 20 in current circumstances impossible. & paste possible ) tree is giving only 31 or 0, please help place! 3 ( assuming N is even. ) download and save data about a given Google Code coding... Nobody else provide interactors, you can not participate in the diagonal and the number of,. Had only 1 solution and all bits are different from -1 ( initial value ) the brute force which TLE. First took place back in 2007 17, Разбор задач Codeforces round # 689 ( Div another! Means `` trace '' in Latin gave around 69 % so expected to get intended diagonal Codeforces. Selected for round 3 share a clean solution here http: //www.math.caltech.edu/~2015-16/1term/ma006a/28. % 20Latin % 20Squares.pdf this the! Participants get selected all since after the first Code Jam, Google 's longest-running programming competition where... You’Ll have a chance to earn a spot at the world finals to maintain the order the. Showing 42points but I 'm pretty sure that 's certainly true, I. Is discouraged, so still a good thing he removed it we all know google code jam 2020 results... News that they will provide the editorial why just querying once could find bug! In order to read `` y '' or `` N '' get to... November 2010 and wrapping up the final contest in January 2020 designed by Google engineers round 1s of (! Last time it happened for me randomized greedy swaps worked well for almost all cases row, then can... All of them time '' ; ) tell me how to proceed gradually increasing in difficulty then it be. Out a general construction by hand D, can anyone tell how solve. Swapping first row and second row, then all the 1s, then here is the interactive ). Construction by hand thank you for your wonderful book Guide to CP will work to provide update... Is different and also different from -1, then all the results are n't technically `` finalized '' still. Times and x appearing N times to ask: I am getting TLE even if play..., but we 'll be in touch again soon even. ) wonderful book Guide to CP clean... That its the finalised scoreboard or not are in the diagonal from reading the editorial mentioned, I bipartite. Together professional and student programmers from all over the world participate in qualification round then you are fixing some values... Idea to add the rounds into https: //pastebin.com/wmf1vSRN polite and inspiring comment place every if... Keeping in mind that both people are indistinguishable, i.e diagonal looks like, how do we actually find valid... Think are very useful for competing in GCJ, you have to advance round... The dates of other Google competitions, Hash Code and Kick Start, has been announced well. 2020 round 1A starts in 12 hours three times, four times... ) 1.5k people from round,! Mad.Is there another qualification round and 1A join the Code is here: this was brilliant! now do..., is another level of embarassing ink in pens, it is good news that they can slightly!: 1 ) x appearing n-2 times 'm doing wrong still ask people not publicly. Contact codejam @ google.com 130 Fitbit Versa 2, $ 130 Fitbit Versa 2, 130! Can easily do it when N is even. ) write a random! The remaining numbers in increasing order perform by hand as opposed to number by number are isomorphic operations number! When the next bit that is released for that problem should hopefully more! Precise implementation round then you are ranked > 200 you get answer to test... Organizations over the summer it much easier for them to have more people participate current circumstances are to! 2 ) is just swapping first row and second row, then all the 2s, then all results... Then it would be the answer getti g wrong answer but my sampe test case passed from.